(2y^2-4y)-(-y^3+2)=0

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Solution for (2y^2-4y)-(-y^3+2)=0 equation: 


Simplifying
(2y2 + -4y) + -1(-1y3 + 2) = 0

Reorder the terms:
(-4y + 2y2) + -1(-1y3 + 2) = 0

Remove parenthesis around (-4y + 2y2)
-4y + 2y2 + -1(-1y3 + 2) = 0

Reorder the terms:
-4y + 2y2 + -1(2 + -1y3) = 0
-4y + 2y2 + (2 * -1 + -1y3 * -1) = 0
-4y + 2y2 + (-2 + 1y3) = 0

Reorder the terms:
-2 + -4y + 2y2 + 1y3 = 0

Solving
-2 + -4y + 2y2 + 1y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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